what kind of electric motor would i need to have enough power to move a 25lbs cart offroad and...?

Question

...avg. about 5-10mph
i am building a remote control cart just for somthing to do and i know how to wire everything up but ive never really been able to tell what motors are good for what job. The cart will end up being no more than 25lbs and will have 4" wheels. i want it to be able to climb hills and such and on flat land be able to average 5-10mph. Any suggestions on a good motor?

Answer 1

What is your expected range? You might get by with a motor rated for 1/5 to 1/3 horsepower. Larger ones will work, but also weigh more. You can get 3/4 to 1 horse permanent magnet motors from old treadmills.



4 inches is rather small for the tires, if you move up to 6 inches, you would fare a little better unless it is a requirement of the device. The taller the tires/wheels the easier to navigate grass and rocks and other uneveness. If you are machining parts, make a CVT so you can take advantage of speed multiplication.



If you are using remote control, and are using a motor control system using PWM, permanent magnet motors will outperform shunt wound motors. and give you best versatility.

Answer 2

Too many unknown factors to figure this...



Need:



a. Angle of incline to climb.

b. Friction coefficient of material climbing.

c. Friction coefficient of wheel contact material.

d. Size of contact patch of wheels.

e. Gear ratio of any transfer box (rear end/ transmission).

f. More...



To calculate out what kind of motor you would need to go 10 MPH on flat land on a 4" wheel the wheel would use 2*Pi*R (Pi=3.14 and R or Radius is 2"--half the diameter). So 2*3.14*2 = 12.56" traveled with each revolution of the wheel.



Then to figure out how many revolutions you need to reach 10 MPH you work backward... take 10 MPH and figure out how many times 12.56" goes into it. First converting it into inches just to make it easy... a mile being 5280 ft. then 10 miles would be 5280 * 10 MPH = 52,800 ft. Convert that to inches... 52,800 * 12 (cause there are 12 inches in a foot) and you get 633,600 inches in one hour (equals 10 MPH).



Once you have that then you just take 633,600 and see how many wheel revolutions it takes to cover it... 633,600" / 12.56" = 50,446 revolutions (rounded up) of the 4" wheel will take your robot 10 miles. Since motors have a rating of RPM (minutes and not hours) you have to convert. A 3400 RPM motor (no load speed) would take a 4" wheel up to 3400 * 60 = 20,400 revs per minute or about 4 MPH. So you need to have an overdrive transmission or a bigger wheel to get more speed. If you want to go 10 MPH and directly driving a 4" wheel this would require a motor going around 55,896 RPM and those are not made. Figure on about 3000 RPM as an average probably. If you overdrive the motor through a transmission you loose a proportional amount of torque (turning power)... all an exercise in compromises.



Things get very complicated... I would recommend you getting Excel (Microsoft spreadseet software) and look up all the calcuations necessary and work them on a spreadsheet. You will need a battery that can provide the wattage (the power) the motors need).



To do this in one hour you should fit that into an number of motors... the highest torque motors you can find will give you the best uphill climbing. I will assume 12VDC (a car battery?). Lots of other calculations to figure to come up with a torque output that will move the cart on flat ground, etc. Can increase friction coefficient by going with tracks (like a tank) to improve friction with the ground fiction is an unknown too... and maybe variable (snow, ice, sand, gravel, loose dirt, mud, etc).

Answer 3

To get a 25 lb cart up a 30 degree incline, off road, at 20 mph, takes 1 hp.



Any 750 watt scooter motor and controller would work just fine.

Answer 4

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